14023001113 has 4 divisors (see below), whose sum is σ = 15297819408. Its totient is φ = 12748182820.

The previous prime is 14023001087. The next prime is 14023001119. The reversal of 14023001113 is 31110032041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14023001113 - 2²¹ = 14020903961 is a prime.

It is a super-3 number, since 3×14023001113³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14023001119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 637409131 + ... + 637409152.

It is an arithmetic number, because the mean of its divisors is an integer number (3824454852).

Almost surely, 2^14023001113 is an apocalyptic number.

It is an amenable number.

14023001113 is a deficient number, since it is larger than the sum of its proper divisors (1274818295).

14023001113 is a wasteful number, since it uses less digits than its factorization.

14023001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1274818294.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 14023001113 its reverse (31110032041), we get a palindrome (45133033154).

The spelling of 14023001113 in words is "fourteen billion, twenty-three million, one thousand, one hundred thirteen".