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1402312061953 = 11214359488061
BaseRepresentation
bin10100011010000000010…
…011111111010000000001
311222001121112112201020001
4110122000103333100001
5140433413341440303
62552114022120001
7203212412566315
oct24320023772001
94861545481201
101402312061953
114a07986676a0
121a793b580001
13a231191327a
144bc2d6d7b45
152672611531d
hex146804ff401

1402312061953 has 8 divisors (see below), whose sum is σ = 1530508859136. Its totient is φ = 1274234245200.

The previous prime is 1402312061933. The next prime is 1402312061971. The reversal of 1402312061953 is 3591602132041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1402312061953 - 25 = 1402312061921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1402312061933) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29720458 + ... + 29767603.

It is an arithmetic number, because the mean of its divisors is an integer number (191313607392).

Almost surely, 21402312061953 is an apocalyptic number.

It is an amenable number.

1402312061953 is a deficient number, since it is larger than the sum of its proper divisors (128196797183).

1402312061953 is a wasteful number, since it uses less digits than its factorization.

1402312061953 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 59490215.

The product of its (nonzero) digits is 38880, while the sum is 37.

Adding to 1402312061953 its reverse (3591602132041), we get a palindrome (4993914193994).

The spelling of 1402312061953 in words is "one trillion, four hundred two billion, three hundred twelve million, sixty-one thousand, nine hundred fifty-three".

Divisors: 1 11 2143 23573 59488061 654368671 127482914723 1402312061953