14023121424041 has 4 divisors (see below), whose sum is σ = 14024711175684. Its totient is φ = 14021531672400.

The previous prime is 14023121424031. The next prime is 14023121424049. The reversal of 14023121424041 is 14042412132041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10403824446016 + 3619296978025 = 3225496^2 + 1902445^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14023121424041 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14023121423995 and 14023121424013.

It is not an unprimeable number, because it can be changed into a prime (14023121424049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 794862590 + ... + 794880231.

It is an arithmetic number, because the mean of its divisors is an integer number (3506177793921).

Almost surely, 2^{14023121424041} is an apocalyptic number.

It is an amenable number.

14023121424041 is a deficient number, since it is larger than the sum of its proper divisors (1589751643).

14023121424041 is an equidigital number, since it uses as much as digits as its factorization.

14023121424041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1589751642.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 14023121424041 its reverse (14042412132041), we get a palindrome (28065533556082).

The spelling of 14023121424041 in words is "fourteen trillion, twenty-three billion, one hundred twenty-one million, four hundred twenty-four thousand, forty-one".