140232340033033 has 4 divisors (see below), whose sum is σ = 141173496677700. Its totient is φ = 139291183388368.

The previous prime is 140232340033003. The next prime is 140232340033087. The reversal of 140232340033033 is 330330043232041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7643632442944 + 132588707590089 = 2764712^2 + 11514717^2 .

It is a cyclic number.

It is not a de Polignac number, because 140232340033033 - 2¹³ = 140232340024841 is a prime.

It is a super-2 number, since 2×140232340033033² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140232340032986 and 140232340033004.

It is not an unprimeable number, because it can be changed into a prime (140232340033003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 470578322110 + ... + 470578322407.

It is an arithmetic number, because the mean of its divisors is an integer number (35293374169425).

Almost surely, 2^{140232340033033} is an apocalyptic number.

It is an amenable number.

140232340033033 is a deficient number, since it is larger than the sum of its proper divisors (941156644667).

140232340033033 is an equidigital number, since it uses as much as digits as its factorization.

140232340033033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 941156644666.

The product of its (nonzero) digits is 46656, while the sum is 31.

Adding to 140232340033033 its reverse (330330043232041), we get a palindrome (470562383265074).

The spelling of 140232340033033 in words is "one hundred forty trillion, two hundred thirty-two billion, three hundred forty million, thirty-three thousand, thirty-three".