Search a number
-
+
140233000233 = 346744333411
BaseRepresentation
bin1000001010011010001…
…0011100010100101001
3111101222002010111222110
42002212202130110221
54244144122001413
6144231103512533
713063050556164
oct2024642342451
9441862114873
10140233000233
1154521966717
12232178b8749
13102bac31a61
146b04560adb
1539ab3e88c3
hex20a689c529

140233000233 has 4 divisors (see below), whose sum is σ = 186977333648. Its totient is φ = 93488666820.

The previous prime is 140233000183. The next prime is 140233000249. The reversal of 140233000233 is 332000332041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 140233000233 - 26 = 140233000169 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (140233000133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23372166703 + ... + 23372166708.

It is an arithmetic number, because the mean of its divisors is an integer number (46744333412).

Almost surely, 2140233000233 is an apocalyptic number.

It is an amenable number.

140233000233 is a deficient number, since it is larger than the sum of its proper divisors (46744333415).

140233000233 is an equidigital number, since it uses as much as digits as its factorization.

140233000233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46744333414.

The product of its (nonzero) digits is 1296, while the sum is 21.

Adding to 140233000233 its reverse (332000332041), we get a palindrome (472233332274).

The spelling of 140233000233 in words is "one hundred forty billion, two hundred thirty-three million, two hundred thirty-three", and thus it is an aban number.

Divisors: 1 3 46744333411 140233000233