Base | Representation |
---|---|
bin | 1100110000010100010101… |
… | …1100001101011100011011 |
3 | 1211122200222221001022200111 |
4 | 3030011011130031130123 |
5 | 3314233112202310233 |
6 | 45454351021345151 |
7 | 2645134400466022 |
oct | 314050534153433 |
9 | 54580887038614 |
10 | 14024233244443 |
11 | 451770a067934 |
12 | 16a5ba74081b7 |
13 | 7a9630677246 |
14 | 366ac2a618b9 |
15 | 194c08613acd |
hex | cc14570d71b |
14024233244443 has 4 divisors (see below), whose sum is σ = 14069039101768. Its totient is φ = 13979427387120.
The previous prime is 14024233244429. The next prime is 14024233244449. The reversal of 14024233244443 is 34444233242041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14024233244443 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14024233244396 and 14024233244405.
It is not an unprimeable number, because it can be changed into a prime (14024233244449) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22402928193 + ... + 22402928818.
It is an arithmetic number, because the mean of its divisors is an integer number (3517259775442).
Almost surely, 214024233244443 is an apocalyptic number.
14024233244443 is a deficient number, since it is larger than the sum of its proper divisors (44805857325).
14024233244443 is an equidigital number, since it uses as much as digits as its factorization.
14024233244443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44805857324.
The product of its (nonzero) digits is 884736, while the sum is 40.
Adding to 14024233244443 its reverse (34444233242041), we get a palindrome (48468466486484).
The spelling of 14024233244443 in words is "fourteen trillion, twenty-four billion, two hundred thirty-three million, two hundred forty-four thousand, four hundred forty-three".
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