140243240031131 has 4 divisors (see below), whose sum is σ = 140247322719264. Its totient is φ = 140239157343000.

The previous prime is 140243240031053. The next prime is 140243240031143. The reversal of 140243240031131 is 131130042342041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140243240031131 - 2¹⁰ = 140243240030107 is a prime.

It is a super-2 number, since 2×140243240031131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140243240031094 and 140243240031103.

It is not an unprimeable number, because it can be changed into a prime (140243240031331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2041292540 + ... + 2041361241.

It is an arithmetic number, because the mean of its divisors is an integer number (35061830679816).

Almost surely, 2^{140243240031131} is an apocalyptic number.

140243240031131 is a deficient number, since it is larger than the sum of its proper divisors (4082688133).

140243240031131 is an equidigital number, since it uses as much as digits as its factorization.

140243240031131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4082688132.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 140243240031131 its reverse (131130042342041), we get a palindrome (271373282373172).

The spelling of 140243240031131 in words is "one hundred forty trillion, two hundred forty-three billion, two hundred forty million, thirty-one thousand, one hundred thirty-one".