Base | Representation |
---|---|
bin | 10100011010000111100… |
… | …110101111110110010001 |
3 | 11222001221001210011001202 |
4 | 110122013212233312101 |
5 | 140434141202420423 |
6 | 2552134112440545 |
7 | 203215426611536 |
oct | 24320746576621 |
9 | 4861831704052 |
10 | 1402434420113 |
11 | 4a085073a141 |
12 | 1a7974549155 |
13 | a233108464c |
14 | 4bc41a68d8d |
15 | 26731c34728 |
hex | 146879afd91 |
1402434420113 has 4 divisors (see below), whose sum is σ = 1402615925760. Its totient is φ = 1402252914468.
The previous prime is 1402434420091. The next prime is 1402434420181. The reversal of 1402434420113 is 3110244342041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1402434420113 - 216 = 1402434354577 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1402434420193) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90741233 + ... + 90756686.
It is an arithmetic number, because the mean of its divisors is an integer number (350653981440).
Almost surely, 21402434420113 is an apocalyptic number.
It is an amenable number.
1402434420113 is a deficient number, since it is larger than the sum of its proper divisors (181505647).
1402434420113 is an equidigital number, since it uses as much as digits as its factorization.
1402434420113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 181505646.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 1402434420113 its reverse (3110244342041), we get a palindrome (4512678762154).
The spelling of 1402434420113 in words is "one trillion, four hundred two billion, four hundred thirty-four million, four hundred twenty thousand, one hundred thirteen".
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