14024405244131 has 4 divisors (see below), whose sum is σ = 14366463908664. Its totient is φ = 13682346579600.

The previous prime is 14024405244119. The next prime is 14024405244217. The reversal of 14024405244131 is 13144250442041.

14024405244131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14024405244131 is a prime.

It is a super-2 number, since 2×14024405244131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14024405244091 and 14024405244100.

It is not an unprimeable number, because it can be changed into a prime (14024405244931) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171029332205 + ... + 171029332286.

It is an arithmetic number, because the mean of its divisors is an integer number (3591615977166).

Almost surely, 2^{14024405244131} is an apocalyptic number.

14024405244131 is a deficient number, since it is larger than the sum of its proper divisors (342058664533).

14024405244131 is an equidigital number, since it uses as much as digits as its factorization.

14024405244131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 342058664532.

The product of its (nonzero) digits is 61440, while the sum is 35.

Adding to 14024405244131 its reverse (13144250442041), we get a palindrome (27168655686172).

The spelling of 14024405244131 in words is "fourteen trillion, twenty-four billion, four hundred five million, two hundred forty-four thousand, one hundred thirty-one".