140244243410033 has 4 divisors (see below), whose sum is σ = 160279135325760. Its totient is φ = 120209351494308.

The previous prime is 140244243409961. The next prime is 140244243410053. The reversal of 140244243410033 is 330014342442041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140244243410033 - 2¹⁸ = 140244243147889 is a prime.

It is a super-2 number, since 2×140244243410033² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 140244243409975 and 140244243410002.

It is not an unprimeable number, because it can be changed into a prime (140244243410053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10017445957853 + ... + 10017445957866.

It is an arithmetic number, because the mean of its divisors is an integer number (40069783831440).

Almost surely, 2^{140244243410033} is an apocalyptic number.

It is an amenable number.

140244243410033 is a deficient number, since it is larger than the sum of its proper divisors (20034891915727).

140244243410033 is an equidigital number, since it uses as much as digits as its factorization.

140244243410033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20034891915726.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 140244243410033 its reverse (330014342442041), we get a palindrome (470258585852074).

The spelling of 140244243410033 in words is "one hundred forty trillion, two hundred forty-four billion, two hundred forty-three million, four hundred ten thousand, thirty-three".