14025113 has 8 divisors (see below), whose sum is σ = 14522880. Its totient is φ = 13530240.

The previous prime is 14025103. The next prime is 14025199. The reversal of 14025113 is 31152041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14025113 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14025091 and 14025100.

It is not an unprimeable number, because it can be changed into a prime (14025103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14633 + ... + 15561.

It is an arithmetic number, because the mean of its divisors is an integer number (1815360).

Almost surely, 2^14025113 is an apocalyptic number.

It is an amenable number.

14025113 is a deficient number, since it is larger than the sum of its proper divisors (497767).

14025113 is an equidigital number, since it uses as much as digits as its factorization.

14025113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1447.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 14025113 is about 3745.0117489802. The cubic root of 14025113 is about 241.1582496283.

Adding to 14025113 its reverse (31152041), we get a palindrome (45177154).

The spelling of 14025113 in words is "fourteen million, twenty-five thousand, one hundred thirteen".