140301114132433 has 4 divisors (see below), whose sum is σ = 143563930740208. Its totient is φ = 137038297524660.

The previous prime is 140301114132427. The next prime is 140301114132527. The reversal of 140301114132433 is 334231411103041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140301114132433 - 2⁵ = 140301114132401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140301114132395 and 140301114132404.

It is not an unprimeable number, because it can be changed into a prime (140301114132733) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1631408303823 + ... + 1631408303908.

It is an arithmetic number, because the mean of its divisors is an integer number (35890982685052).

Almost surely, 2^{140301114132433} is an apocalyptic number.

It is an amenable number.

140301114132433 is a deficient number, since it is larger than the sum of its proper divisors (3262816607775).

140301114132433 is an equidigital number, since it uses as much as digits as its factorization.

140301114132433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3262816607774.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 140301114132433 its reverse (334231411103041), we get a palindrome (474532525235474).

The spelling of 140301114132433 in words is "one hundred forty trillion, three hundred one billion, one hundred fourteen million, one hundred thirty-two thousand, four hundred thirty-three".