14031324332131 has 4 divisors (see below), whose sum is σ = 14032175712264. Its totient is φ = 14030472952000.

The previous prime is 14031324332087. The next prime is 14031324332159. The reversal of 14031324332131 is 13123342313041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14031324332131 - 2¹¹ = 14031324330083 is a prime.

It is a super-2 number, since 2×14031324332131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14031324332093 and 14031324332102.

It is not an unprimeable number, because it can be changed into a prime (14031324335131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 425665345 + ... + 425698306.

It is an arithmetic number, because the mean of its divisors is an integer number (3508043928066).

Almost surely, 2^{14031324332131} is an apocalyptic number.

14031324332131 is a deficient number, since it is larger than the sum of its proper divisors (851380133).

14031324332131 is an equidigital number, since it uses as much as digits as its factorization.

14031324332131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 851380132.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 14031324332131 its reverse (13123342313041), we get a palindrome (27154666645172).

The spelling of 14031324332131 in words is "fourteen trillion, thirty-one billion, three hundred twenty-four million, three hundred thirty-two thousand, one hundred thirty-one".