140314433 has 4 divisors (see below), whose sum is σ = 160359360. Its totient is φ = 120269508.

The previous prime is 140314429. The next prime is 140314451. The reversal of 140314433 is 334413041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 334413041 = 61 ⋅5482181.

It is a cyclic number.

It is not a de Polignac number, because 140314433 - 2² = 140314429 is a prime.

It is a super-2 number, since 2×140314433² = 39376280216222978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140314399 and 140314408.

It is not an unprimeable number, because it can be changed into a prime (140314133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10022453 + ... + 10022466.

It is an arithmetic number, because the mean of its divisors is an integer number (40089840).

Almost surely, 2^140314433 is an apocalyptic number.

It is an amenable number.

140314433 is a deficient number, since it is larger than the sum of its proper divisors (20044927).

140314433 is an equidigital number, since it uses as much as digits as its factorization.

140314433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20044926.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 140314433 is about 11845.4393333468. The cubic root of 140314433 is about 519.6378555914.

Adding to 140314433 its reverse (334413041), we get a palindrome (474727474).

The spelling of 140314433 in words is "one hundred forty million, three hundred fourteen thousand, four hundred thirty-three".