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140320001113 = 1306211074253
BaseRepresentation
bin1000001010101110111…
…0010100110001011001
3111102012010211121202021
42002223232110301121
54244333410013423
6144243452334441
713065155221105
oct2025356246131
9442163747667
10140320001113
1154566a89776
1223240a74421
1310302c73876
146b11d2a905
1539b3d8195d
hex20abb94c59

140320001113 has 4 divisors (see below), whose sum is σ = 140321205988. Its totient is φ = 140318796240.

The previous prime is 140320001111. The next prime is 140320001147. The reversal of 140320001113 is 311100023041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 22583176729 + 117736824384 = 150277^2 + 343128^2 .

It is a cyclic number.

It is not a de Polignac number, because 140320001113 - 21 = 140320001111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140320001111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 406506 + ... + 667747.

It is an arithmetic number, because the mean of its divisors is an integer number (35080301497).

Almost surely, 2140320001113 is an apocalyptic number.

It is an amenable number.

140320001113 is a deficient number, since it is larger than the sum of its proper divisors (1204875).

140320001113 is a wasteful number, since it uses less digits than its factorization.

140320001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1204874.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 140320001113 its reverse (311100023041), we get a palindrome (451420024154).

The spelling of 140320001113 in words is "one hundred forty billion, three hundred twenty million, one thousand, one hundred thirteen".

Divisors: 1 130621 1074253 140320001113