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14032410411 = 34677470137
BaseRepresentation
bin11010001000110010…
…11001011100101011
31100012221110022022010
431010121121130223
5212214244113121
610240231131003
71004510343345
oct150431313453
940187408263
1014032410411
115a50a256a8
122877513a63
131428249036
14971912295
15571dd6376
hex34465972b

14032410411 has 4 divisors (see below), whose sum is σ = 18709880552. Its totient is φ = 9354940272.

The previous prime is 14032410401. The next prime is 14032410439. The reversal of 14032410411 is 11401423041.

14032410411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11401423041 = 33800474347.

It is not a de Polignac number, because 14032410411 - 218 = 14032148267 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14032410401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2338735066 + ... + 2338735071.

It is an arithmetic number, because the mean of its divisors is an integer number (4677470138).

Almost surely, 214032410411 is an apocalyptic number.

14032410411 is a deficient number, since it is larger than the sum of its proper divisors (4677470141).

14032410411 is an equidigital number, since it uses as much as digits as its factorization.

14032410411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4677470140.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 14032410411 its reverse (11401423041), we get a palindrome (25433833452).

The spelling of 14032410411 in words is "fourteen billion, thirty-two million, four hundred ten thousand, four hundred eleven".

Divisors: 1 3 4677470137 14032410411