Base | Representation |
---|---|
bin | 1100110000110010110101… |
… | …1111001100111000111011 |
3 | 1211200111010120100011001012 |
4 | 3030030231133030320323 |
5 | 3314401344323410021 |
6 | 45502223320144135 |
7 | 2645544324056216 |
oct | 314145537147073 |
9 | 54614116304035 |
10 | 14032421310011 |
11 | 4520131006775 |
12 | 16a76b160804b |
13 | 7aa336b56460 |
14 | 36725c2c277d |
15 | 1950373ac35b |
hex | cc32d7cce3b |
14032421310011 has 4 divisors (see below), whose sum is σ = 15111838333872. Its totient is φ = 12953004286152.
The previous prime is 14032421309953. The next prime is 14032421310023. The reversal of 14032421310011 is 11001312423041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14032421310011 - 218 = 14032421047867 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14032421313011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 539708511911 + ... + 539708511936.
It is an arithmetic number, because the mean of its divisors is an integer number (3777959583468).
Almost surely, 214032421310011 is an apocalyptic number.
14032421310011 is a deficient number, since it is larger than the sum of its proper divisors (1079417023861).
14032421310011 is a wasteful number, since it uses less digits than its factorization.
14032421310011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1079417023860.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 14032421310011 its reverse (11001312423041), we get a palindrome (25033733733052).
The spelling of 14032421310011 in words is "fourteen trillion, thirty-two billion, four hundred twenty-one million, three hundred ten thousand, eleven".
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