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140325016153 = 7173115875323
BaseRepresentation
bin1000001010110000000…
…1011101001001011001
3111102012111021102002111
42002230001131021121
54244341201004103
6144244152032321
713065245646160
oct2025401351131
9442174242074
10140325016153
11545698a4633
12232426926a1
131030400b44a
146b128743d7
1539b452286d
hex20ac05d259

140325016153 has 8 divisors (see below), whose sum is σ = 161298451008. Its totient is φ = 119583332304.

The previous prime is 140325016151. The next prime is 140325016163. The reversal of 140325016153 is 351610523041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 140325016153 - 21 = 140325016151 is a prime.

It is a super-2 number, since 2×1403250161532 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140325016151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57936451 + ... + 57938872.

It is an arithmetic number, because the mean of its divisors is an integer number (20162306376).

Almost surely, 2140325016153 is an apocalyptic number.

It is an amenable number.

140325016153 is a deficient number, since it is larger than the sum of its proper divisors (20973434855).

140325016153 is a wasteful number, since it uses less digits than its factorization.

140325016153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 115875503.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 140325016153 its reverse (351610523041), we get a palindrome (491935539194).

The spelling of 140325016153 in words is "one hundred forty billion, three hundred twenty-five million, sixteen thousand, one hundred fifty-three".

Divisors: 1 7 173 1211 115875323 811127261 20046430879 140325016153