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14034005411 = 98711421741
BaseRepresentation
bin11010001000111110…
…11110110110100011
31100020001110100020012
431010133132312203
5212220201133121
610240325235135
71004530035446
oct150437366643
940201410205
1014034005411
115a51914a88
122877b62aab
13142868701a
14971c0965d
155720edc5b
hex3447deda3

14034005411 has 4 divisors (see below), whose sum is σ = 14035437024. Its totient is φ = 14032573800.

The previous prime is 14034005371. The next prime is 14034005423. The reversal of 14034005411 is 11450043041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11450043041 = 89128652169.

It is a cyclic number.

It is not a de Polignac number, because 14034005411 - 226 = 13966896547 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14034005431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 701000 + ... + 720741.

It is an arithmetic number, because the mean of its divisors is an integer number (3508859256).

Almost surely, 214034005411 is an apocalyptic number.

14034005411 is a deficient number, since it is larger than the sum of its proper divisors (1431613).

14034005411 is an equidigital number, since it uses as much as digits as its factorization.

14034005411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1431612.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 14034005411 its reverse (11450043041), we get a palindrome (25484048452).

The spelling of 14034005411 in words is "fourteen billion, thirty-four million, five thousand, four hundred eleven".

Divisors: 1 9871 1421741 14034005411