140341313112041 has 4 divisors (see below), whose sum is σ = 141350962846800. Its totient is φ = 139331663377284.

The previous prime is 140341313112001. The next prime is 140341313112071. The reversal of 140341313112041 is 140211313143041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140341313112041 - 2¹⁰ = 140341313111017 is a prime.

It is a super-2 number, since 2×140341313112041² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140341313111995 and 140341313112013.

It is not an unprimeable number, because it can be changed into a prime (140341313112001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504824867171 + ... + 504824867448.

It is an arithmetic number, because the mean of its divisors is an integer number (35337740711700).

Almost surely, 2^{140341313112041} is an apocalyptic number.

It is an amenable number.

140341313112041 is a deficient number, since it is larger than the sum of its proper divisors (1009649734759).

140341313112041 is a wasteful number, since it uses less digits than its factorization.

140341313112041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1009649734758.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 140341313112041 its reverse (140211313143041), we get a palindrome (280552626255082).

The spelling of 140341313112041 in words is "one hundred forty trillion, three hundred forty-one billion, three hundred thirteen million, one hundred twelve thousand, forty-one".