140342015330401 has 4 divisors (see below), whose sum is σ = 142720693556400. Its totient is φ = 137963337104404.

The previous prime is 140342015330399. The next prime is 140342015330411. The reversal of 140342015330401 is 104033510243041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140342015330401 - 2¹ = 140342015330399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140342015330411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1189339112911 + ... + 1189339113028.

It is an arithmetic number, because the mean of its divisors is an integer number (35680173389100).

Almost surely, 2^{140342015330401} is an apocalyptic number.

It is an amenable number.

140342015330401 is a deficient number, since it is larger than the sum of its proper divisors (2378678225999).

140342015330401 is an equidigital number, since it uses as much as digits as its factorization.

140342015330401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2378678225998.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 140342015330401 its reverse (104033510243041), we get a palindrome (244375525573442).

The spelling of 140342015330401 in words is "one hundred forty trillion, three hundred forty-two billion, fifteen million, three hundred thirty thousand, four hundred one".