14034340433 has 4 divisors (see below), whose sum is σ = 14035227648. Its totient is φ = 14033453220.

The previous prime is 14034340403. The next prime is 14034340451. The reversal of 14034340433 is 33404343041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14034340433 - 2¹⁶ = 14034274897 is a prime.

It is a super-2 number, since 2×14034340433² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14034340396 and 14034340405.

It is not an unprimeable number, because it can be changed into a prime (14034340403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 419441 + ... + 451662.

It is an arithmetic number, because the mean of its divisors is an integer number (3508806912).

Almost surely, 2^14034340433 is an apocalyptic number.

It is an amenable number.

14034340433 is a deficient number, since it is larger than the sum of its proper divisors (887215).

14034340433 is an equidigital number, since it uses as much as digits as its factorization.

14034340433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 887214.

The product of its (nonzero) digits is 20736, while the sum is 29.

Adding to 14034340433 its reverse (33404343041), we get a palindrome (47438683474).

The spelling of 14034340433 in words is "fourteen billion, thirty-four million, three hundred forty thousand, four hundred thirty-three".