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14035244430355 = 52807048886071
BaseRepresentation
bin1100110000111101010111…
…0000100011010000010011
31211200202102022112112002221
43030033111300203100103
53314423140033232410
645503411405321511
72646004304150611
oct314172560432023
954622368475087
1014035244430355
11452134a645885
1216a815ab66297
137aa6969ba175
143674492046b1
151951501624da
hexcc3d5c23413

14035244430355 has 4 divisors (see below), whose sum is σ = 16842293316432. Its totient is φ = 11228195544280.

The previous prime is 14035244430331. The next prime is 14035244430371. The reversal of 14035244430355 is 55303444253041.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-14035244430355 is a prime.

It is a super-2 number, since 2×140352444303552 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1403524443031 + ... + 1403524443040.

It is an arithmetic number, because the mean of its divisors is an integer number (4210573329108).

Almost surely, 214035244430355 is an apocalyptic number.

14035244430355 is a deficient number, since it is larger than the sum of its proper divisors (2807048886077).

14035244430355 is an equidigital number, since it uses as much as digits as its factorization.

14035244430355 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2807048886076.

The product of its (nonzero) digits is 1728000, while the sum is 43.

Adding to 14035244430355 its reverse (55303444253041), we get a palindrome (69338688683396).

The spelling of 14035244430355 in words is "fourteen trillion, thirty-five billion, two hundred forty-four million, four hundred thirty thousand, three hundred fifty-five".

Divisors: 1 5 2807048886071 14035244430355