Base | Representation |
---|---|
bin | 1100110000111101010111… |
… | …0000100011010000010011 |
3 | 1211200202102022112112002221 |
4 | 3030033111300203100103 |
5 | 3314423140033232410 |
6 | 45503411405321511 |
7 | 2646004304150611 |
oct | 314172560432023 |
9 | 54622368475087 |
10 | 14035244430355 |
11 | 452134a645885 |
12 | 16a815ab66297 |
13 | 7aa6969ba175 |
14 | 3674492046b1 |
15 | 1951501624da |
hex | cc3d5c23413 |
14035244430355 has 4 divisors (see below), whose sum is σ = 16842293316432. Its totient is φ = 11228195544280.
The previous prime is 14035244430331. The next prime is 14035244430371. The reversal of 14035244430355 is 55303444253041.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-14035244430355 is a prime.
It is a super-2 number, since 2×140352444303552 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1403524443031 + ... + 1403524443040.
It is an arithmetic number, because the mean of its divisors is an integer number (4210573329108).
Almost surely, 214035244430355 is an apocalyptic number.
14035244430355 is a deficient number, since it is larger than the sum of its proper divisors (2807048886077).
14035244430355 is an equidigital number, since it uses as much as digits as its factorization.
14035244430355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2807048886076.
The product of its (nonzero) digits is 1728000, while the sum is 43.
Adding to 14035244430355 its reverse (55303444253041), we get a palindrome (69338688683396).
The spelling of 14035244430355 in words is "fourteen trillion, thirty-five billion, two hundred forty-four million, four hundred thirty thousand, three hundred fifty-five".
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