Base | Representation |
---|---|
bin | 1100110001001110111010… |
… | …1111010001100111010011 |
3 | 1211201012120211212202020211 |
4 | 3030103232233101213103 |
5 | 3320012313333244101 |
6 | 45505511244144551 |
7 | 2646232155060436 |
oct | 314235657214723 |
9 | 54635524782224 |
10 | 14039958493651 |
11 | 4523349604362 |
12 | 16a9055838157 |
13 | 7aac6853312c |
14 | 36777531381d |
15 | 195328e36c51 |
hex | cc4eebd19d3 |
14039958493651 has 4 divisors (see below), whose sum is σ = 14039995737672. Its totient is φ = 14039921249632.
The previous prime is 14039958493637. The next prime is 14039958493657. The reversal of 14039958493651 is 15639485993041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14039958493651 - 29 = 14039958493139 is a prime.
It is a Smith number, since the sum of its digits (67) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14039958493657) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18050710 + ... + 18812443.
It is an arithmetic number, because the mean of its divisors is an integer number (3509998934418).
Almost surely, 214039958493651 is an apocalyptic number.
14039958493651 is a deficient number, since it is larger than the sum of its proper divisors (37244021).
14039958493651 is an equidigital number, since it uses as much as digits as its factorization.
14039958493651 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37244020.
The product of its (nonzero) digits is 125971200, while the sum is 67.
The spelling of 14039958493651 in words is "fourteen trillion, thirty-nine billion, nine hundred fifty-eight million, four hundred ninety-three thousand, six hundred fifty-one".
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