14040044323321 has 4 divisors (see below), whose sum is σ = 14492948978944. Its totient is φ = 13587139667700.

The previous prime is 14040044323303. The next prime is 14040044323339. The reversal of 14040044323321 is 12332344004041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (14040044323303) and next prime (14040044323339).

It is a cyclic number.

It is not a de Polignac number, because 14040044323321 - 2⁹ = 14040044322809 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (31), and also a Moran number because the ratio is a prime number: 452904655591 = 14040044323321 / (1 + 4 + 0 + 4 + 0 + 0 + 4 + 4 + 3 + 2 + 3 + 3 + 2 + 1).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14040044323301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226452327765 + ... + 226452327826.

It is an arithmetic number, because the mean of its divisors is an integer number (3623237244736).

Almost surely, 2^{14040044323321} is an apocalyptic number.

It is an amenable number.

14040044323321 is a deficient number, since it is larger than the sum of its proper divisors (452904655623).

14040044323321 is an equidigital number, since it uses as much as digits as its factorization.

14040044323321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 452904655622.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 14040044323321 its reverse (12332344004041), we get a palindrome (26372388327362).

The spelling of 14040044323321 in words is "fourteen trillion, forty billion, forty-four million, three hundred twenty-three thousand, three hundred twenty-one".