14040052224403 has 4 divisors (see below), whose sum is σ = 14040061348968. Its totient is φ = 14040043099840.

The previous prime is 14040052224377. The next prime is 14040052224461. The reversal of 14040052224403 is 30442225004041.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14040052224403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14040052204403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1623001 + ... + 5542042.

It is an arithmetic number, because the mean of its divisors is an integer number (3510015337242).

Almost surely, 2^{14040052224403} is an apocalyptic number.

14040052224403 is a deficient number, since it is larger than the sum of its proper divisors (9124565).

14040052224403 is an equidigital number, since it uses as much as digits as its factorization.

14040052224403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9124564.

The product of its (nonzero) digits is 30720, while the sum is 31.

Adding to 14040052224403 its reverse (30442225004041), we get a palindrome (44482277228444).

The spelling of 14040052224403 in words is "fourteen trillion, forty billion, fifty-two million, two hundred twenty-four thousand, four hundred three".