140401412113331 has 4 divisors (see below), whose sum is σ = 143825836799064. Its totient is φ = 136976987427600.

The previous prime is 140401412113301. The next prime is 140401412113357. The reversal of 140401412113331 is 133311214104041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140401412113331 - 2¹⁸ = 140401411851187 is a prime.

It is a super-2 number, since 2×140401412113331² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140401412113294 and 140401412113303.

It is not an unprimeable number, because it can be changed into a prime (140401412113301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1712212342805 + ... + 1712212342886.

It is an arithmetic number, because the mean of its divisors is an integer number (35956459199766).

Almost surely, 2^{140401412113331} is an apocalyptic number.

140401412113331 is a deficient number, since it is larger than the sum of its proper divisors (3424424685733).

140401412113331 is an equidigital number, since it uses as much as digits as its factorization.

140401412113331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3424424685732.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 140401412113331 its reverse (133311214104041), we get a palindrome (273712626217372).

The spelling of 140401412113331 in words is "one hundred forty trillion, four hundred one billion, four hundred twelve million, one hundred thirteen thousand, three hundred thirty-one".