14041124111123 has 4 divisors (see below), whose sum is σ = 14525300804640. Its totient is φ = 13556947417608.

The previous prime is 14041124111099. The next prime is 14041124111141. The reversal of 14041124111123 is 32111142114041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14041124111123 - 2¹⁰ = 14041124110099 is a prime.

It is a super-2 number, since 2×14041124111123² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14041124111092 and 14041124111101.

It is not an unprimeable number, because it can be changed into a prime (14041124111143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242088346715 + ... + 242088346772.

It is an arithmetic number, because the mean of its divisors is an integer number (3631325201160).

Almost surely, 2^{14041124111123} is an apocalyptic number.

14041124111123 is a deficient number, since it is larger than the sum of its proper divisors (484176693517).

14041124111123 is an equidigital number, since it uses as much as digits as its factorization.

14041124111123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 484176693516.

The product of its (nonzero) digits is 768, while the sum is 26.

Adding to 14041124111123 its reverse (32111142114041), we get a palindrome (46152266225164).

The spelling of 14041124111123 in words is "fourteen trillion, forty-one billion, one hundred twenty-four million, one hundred eleven thousand, one hundred twenty-three".