Base | Representation |
---|---|
bin | 1100110001010111011001… |
… | …0111101010001110110011 |
3 | 1211201102110102122200011211 |
4 | 3030111312113222032303 |
5 | 3320031443401120103 |
6 | 45510525132220551 |
7 | 2646342435434533 |
oct | 314256627521663 |
9 | 54642412580154 |
10 | 14042234004403 |
11 | 4524307019260 |
12 | 16a958b90a757 |
13 | 7ab23bab26b7 |
14 | 36790d6094c3 |
15 | 19540dabc36d |
hex | cc5765ea3b3 |
14042234004403 has 8 divisors (see below), whose sum is σ = 15318864101376. Its totient is φ = 12765614469000.
The previous prime is 14042234004377. The next prime is 14042234004467. The reversal of 14042234004403 is 30440043224041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14042234004403 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14042234004103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 280050 + ... + 5306872.
It is an arithmetic number, because the mean of its divisors is an integer number (1914858012672).
Almost surely, 214042234004403 is an apocalyptic number.
14042234004403 is a deficient number, since it is larger than the sum of its proper divisors (1276630096973).
14042234004403 is a wasteful number, since it uses less digits than its factorization.
14042234004403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5280785.
The product of its (nonzero) digits is 36864, while the sum is 31.
Adding to 14042234004403 its reverse (30440043224041), we get a palindrome (44482277228444).
The spelling of 14042234004403 in words is "fourteen trillion, forty-two billion, two hundred thirty-four million, four thousand, four hundred three".
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