140423211251331 has 8 divisors (see below), whose sum is σ = 187427413132560. Its totient is φ = 93517241768832.

The previous prime is 140423211251293. The next prime is 140423211251339. The reversal of 140423211251331 is 133152112324041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 140423211251331 - 2¹⁰ = 140423211250307 is a prime.

It is a super-2 number, since 2×140423211251331² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140423211251292 and 140423211251301.

It is not an unprimeable number, because it can be changed into a prime (140423211251339) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24558096346 + ... + 24558102063.

It is an arithmetic number, because the mean of its divisors is an integer number (23428426641570).

Almost surely, 2^{140423211251331} is an apocalyptic number.

140423211251331 is a deficient number, since it is larger than the sum of its proper divisors (47004201881229).

140423211251331 is an equidigital number, since it uses as much as digits as its factorization.

140423211251331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49116199365.

The product of its (nonzero) digits is 17280, while the sum is 33.

Adding to 140423211251331 its reverse (133152112324041), we get a palindrome (273575323575372).

The spelling of 140423211251331 in words is "one hundred forty trillion, four hundred twenty-three billion, two hundred eleven million, two hundred fifty-one thousand, three hundred thirty-one".