Base | Representation |
---|---|
bin | 11111111011011101010010… |
… | …001001101011110110101011 |
3 | 200102012112022222020010120221 |
4 | 133323131102021223312223 |
5 | 121401212041001411410 |
6 | 1214354301411030511 |
7 | 41402252453533246 |
oct | 3773352211536653 |
9 | 612175288203527 |
10 | 140425334013355 |
11 | 40820060195866 |
12 | 138bb45429b437 |
13 | 604808a831991 |
14 | 269689dd4225d |
15 | 1137bba0844da |
hex | 7fb75226bdab |
140425334013355 has 8 divisors (see below), whose sum is σ = 168637963580064. Its totient is φ = 112255225368000.
The previous prime is 140425334013343. The next prime is 140425334013359. The reversal of 140425334013355 is 553310433524041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 140425334013355 - 25 = 140425334013323 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (140425334013359) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10630223071 + ... + 10630236280.
It is an arithmetic number, because the mean of its divisors is an integer number (21079745447508).
Almost surely, 2140425334013355 is an apocalyptic number.
140425334013355 is a deficient number, since it is larger than the sum of its proper divisors (28212629566709).
140425334013355 is a wasteful number, since it uses less digits than its factorization.
140425334013355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21260460677.
The product of its (nonzero) digits is 1296000, while the sum is 43.
Adding to 140425334013355 its reverse (553310433524041), we get a palindrome (693735767537396).
The spelling of 140425334013355 in words is "one hundred forty trillion, four hundred twenty-five billion, three hundred thirty-four million, thirteen thousand, three hundred fifty-five".
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