14043220143131 has 4 divisors (see below), whose sum is σ = 14043229381632. Its totient is φ = 14043210904632.

The previous prime is 14043220143119. The next prime is 14043220143163. The reversal of 14043220143131 is 13134102234041.

14043220143131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14043220143131 is a prime.

It is a super-2 number, since 2×14043220143131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14043220143094 and 14043220143103.

It is not an unprimeable number, because it can be changed into a prime (14043220143031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1741556 + ... + 5578481.

It is an arithmetic number, because the mean of its divisors is an integer number (3510807345408).

Almost surely, 2^{14043220143131} is an apocalyptic number.

14043220143131 is a deficient number, since it is larger than the sum of its proper divisors (9238501).

14043220143131 is an equidigital number, since it uses as much as digits as its factorization.

14043220143131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9238500.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 14043220143131 its reverse (13134102234041), we get a palindrome (27177322377172).

The spelling of 14043220143131 in words is "fourteen trillion, forty-three billion, two hundred twenty million, one hundred forty-three thousand, one hundred thirty-one".