Base | Representation |
---|---|
bin | 1100110001011011011000… |
… | …1001011100100101111001 |
3 | 1211201112020000002010002220 |
4 | 3030112312021130211321 |
5 | 3320041141312122340 |
6 | 45511223234314253 |
7 | 2646411110426535 |
oct | 314266611344571 |
9 | 54645200063086 |
10 | 14043304020345 |
11 | 4524806014056 |
12 | 16a982a128989 |
13 | 7ab37c695722 |
14 | 3679b1780bc5 |
15 | 1954729cded0 |
hex | cc5b625c979 |
14043304020345 has 16 divisors (see below), whose sum is σ = 22469749351872. Its totient is φ = 7489607837760.
The previous prime is 14043304020331. The next prime is 14043304020439. The reversal of 14043304020345 is 54302040334041.
It is not a de Polignac number, because 14043304020345 - 24 = 14043304020329 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8889907 + ... + 10349736.
It is an arithmetic number, because the mean of its divisors is an integer number (1404359334492).
Almost surely, 214043304020345 is an apocalyptic number.
14043304020345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
14043304020345 is a deficient number, since it is larger than the sum of its proper divisors (8426445331527).
14043304020345 is a wasteful number, since it uses less digits than its factorization.
14043304020345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19288312.
The product of its (nonzero) digits is 69120, while the sum is 33.
Adding to 14043304020345 its reverse (54302040334041), we get a palindrome (68345344354386).
The spelling of 14043304020345 in words is "fourteen trillion, forty-three billion, three hundred four million, twenty thousand, three hundred forty-five".
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