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14043304020345 = 354866119239643
BaseRepresentation
bin1100110001011011011000…
…1001011100100101111001
31211201112020000002010002220
43030112312021130211321
53320041141312122340
645511223234314253
72646411110426535
oct314266611344571
954645200063086
1014043304020345
114524806014056
1216a982a128989
137ab37c695722
143679b1780bc5
151954729cded0
hexcc5b625c979

14043304020345 has 16 divisors (see below), whose sum is σ = 22469749351872. Its totient is φ = 7489607837760.

The previous prime is 14043304020331. The next prime is 14043304020439. The reversal of 14043304020345 is 54302040334041.

It is not a de Polignac number, because 14043304020345 - 24 = 14043304020329 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8889907 + ... + 10349736.

It is an arithmetic number, because the mean of its divisors is an integer number (1404359334492).

Almost surely, 214043304020345 is an apocalyptic number.

14043304020345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

14043304020345 is a deficient number, since it is larger than the sum of its proper divisors (8426445331527).

14043304020345 is a wasteful number, since it uses less digits than its factorization.

14043304020345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19288312.

The product of its (nonzero) digits is 69120, while the sum is 33.

Adding to 14043304020345 its reverse (54302040334041), we get a palindrome (68345344354386).

The spelling of 14043304020345 in words is "fourteen trillion, forty-three billion, three hundred four million, twenty thousand, three hundred forty-five".

Divisors: 1 3 5 15 48661 145983 243305 729915 19239643 57718929 96198215 288594645 936220268023 2808660804069 4681101340115 14043304020345