Base | Representation |
---|---|
bin | 11010001010000110… |
… | …01000010100100001 |
3 | 1100020201001010000101 |
4 | 31011003020110201 |
5 | 212230044202210 |
6 | 10241301422401 |
7 | 1005002336155 |
oct | 150503102441 |
9 | 40221033011 |
10 | 14043350305 |
11 | 5a57117a36 |
12 | 287b10aa01 |
13 | 142a5a964a |
14 | 97315d065 |
15 | 572d47a3a |
hex | 3450c8521 |
14043350305 has 4 divisors (see below), whose sum is σ = 16852020372. Its totient is φ = 11234680240.
The previous prime is 14043350297. The next prime is 14043350323. The reversal of 14043350305 is 50305334041.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 50305334041 = 31 ⋅1622752711.
It can be written as a sum of positive squares in 2 ways, for example, as 9269645841 + 4773704464 = 96279^2 + 69092^2 .
It is not a de Polignac number, because 14043350305 - 23 = 14043350297 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1404335026 + ... + 1404335035.
It is an arithmetic number, because the mean of its divisors is an integer number (4213005093).
Almost surely, 214043350305 is an apocalyptic number.
It is an amenable number.
14043350305 is a deficient number, since it is larger than the sum of its proper divisors (2808670067).
14043350305 is an equidigital number, since it uses as much as digits as its factorization.
14043350305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2808670066.
The product of its (nonzero) digits is 10800, while the sum is 28.
Adding to 14043350305 its reverse (50305334041), we get a palindrome (64348684346).
The spelling of 14043350305 in words is "fourteen billion, forty-three million, three hundred fifty thousand, three hundred five".
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