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14043350305 = 52808670061
BaseRepresentation
bin11010001010000110…
…01000010100100001
31100020201001010000101
431011003020110201
5212230044202210
610241301422401
71005002336155
oct150503102441
940221033011
1014043350305
115a57117a36
12287b10aa01
13142a5a964a
1497315d065
15572d47a3a
hex3450c8521

14043350305 has 4 divisors (see below), whose sum is σ = 16852020372. Its totient is φ = 11234680240.

The previous prime is 14043350297. The next prime is 14043350323. The reversal of 14043350305 is 50305334041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 50305334041 = 311622752711.

It can be written as a sum of positive squares in 2 ways, for example, as 9269645841 + 4773704464 = 96279^2 + 69092^2 .

It is not a de Polignac number, because 14043350305 - 23 = 14043350297 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1404335026 + ... + 1404335035.

It is an arithmetic number, because the mean of its divisors is an integer number (4213005093).

Almost surely, 214043350305 is an apocalyptic number.

It is an amenable number.

14043350305 is a deficient number, since it is larger than the sum of its proper divisors (2808670067).

14043350305 is an equidigital number, since it uses as much as digits as its factorization.

14043350305 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2808670066.

The product of its (nonzero) digits is 10800, while the sum is 28.

Adding to 14043350305 its reverse (50305334041), we get a palindrome (64348684346).

The spelling of 14043350305 in words is "fourteen billion, forty-three million, three hundred fifty thousand, three hundred five".

Divisors: 1 5 2808670061 14043350305