14043926127241 has 4 divisors (see below), whose sum is σ = 14044713404800. Its totient is φ = 14043138849684.

The previous prime is 14043926127229. The next prime is 14043926127271. The reversal of 14043926127241 is 14272162934041.

14043926127241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14043926127241 - 2¹³ = 14043926119049 is a prime.

It is a super-4 number, since 4×14043926127241⁴ (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14043926127191 and 14043926127200.

It is not an unprimeable number, because it can be changed into a prime (14043926127271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 393612021 + ... + 393647698.

It is an arithmetic number, because the mean of its divisors is an integer number (3511178351200).

Almost surely, 2^{14043926127241} is an apocalyptic number.

It is an amenable number.

14043926127241 is a deficient number, since it is larger than the sum of its proper divisors (787277559).

14043926127241 is an equidigital number, since it uses as much as digits as its factorization.

14043926127241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 787277558.

The product of its (nonzero) digits is 580608, while the sum is 46.

The spelling of 14043926127241 in words is "fourteen trillion, forty-three billion, nine hundred twenty-six million, one hundred twenty-seven thousand, two hundred forty-one".