140442224023113 has 4 divisors (see below), whose sum is σ = 187256298697488. Its totient is φ = 93628149348740.

The previous prime is 140442224023111. The next prime is 140442224023193. The reversal of 140442224023113 is 311320422244041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140442224023113 - 2¹ = 140442224023111 is a prime.

It is not an unprimeable number, because it can be changed into a prime (140442224023111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23407037337183 + ... + 23407037337188.

It is an arithmetic number, because the mean of its divisors is an integer number (46814074674372).

Almost surely, 2^{140442224023113} is an apocalyptic number.

It is an amenable number.

140442224023113 is a deficient number, since it is larger than the sum of its proper divisors (46814074674375).

140442224023113 is an equidigital number, since it uses as much as digits as its factorization.

140442224023113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46814074674374.

The product of its (nonzero) digits is 36864, while the sum is 33.

Adding to 140442224023113 its reverse (311320422244041), we get a palindrome (451762646267154).

The spelling of 140442224023113 in words is "one hundred forty trillion, four hundred forty-two billion, two hundred twenty-four million, twenty-three thousand, one hundred thirteen".