14044440433 has 4 divisors (see below), whose sum is σ = 14222218240. Its totient is φ = 13866662628.

The previous prime is 14044440391. The next prime is 14044440451. The reversal of 14044440433 is 33404444041.

14044440433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14044440433 - 2⁹ = 14044439921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14044440395 and 14044440404.

It is not an unprimeable number, because it can be changed into a prime (14044440533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88888785 + ... + 88888942.

It is an arithmetic number, because the mean of its divisors is an integer number (3555554560).

Almost surely, 2^14044440433 is an apocalyptic number.

It is an amenable number.

14044440433 is a deficient number, since it is larger than the sum of its proper divisors (177777807).

14044440433 is an equidigital number, since it uses as much as digits as its factorization.

14044440433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 177777806.

The product of its (nonzero) digits is 36864, while the sum is 31.

Adding to 14044440433 its reverse (33404444041), we get a palindrome (47448884474).

The spelling of 14044440433 in words is "fourteen billion, forty-four million, four hundred forty thousand, four hundred thirty-three".