140445233113 has 4 divisors (see below), whose sum is σ = 140446124560. Its totient is φ = 140444341668.

The previous prime is 140445233099. The next prime is 140445233141. The reversal of 140445233113 is 311332544041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 140445233113 - 2⁹ = 140445232601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140445233413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139083 + ... + 547936.

It is an arithmetic number, because the mean of its divisors is an integer number (35111531140).

Almost surely, 2^140445233113 is an apocalyptic number.

It is an amenable number.

140445233113 is a deficient number, since it is larger than the sum of its proper divisors (891447).

140445233113 is an equidigital number, since it uses as much as digits as its factorization.

140445233113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 891446.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 140445233113 its reverse (311332544041), we get a palindrome (451777777154).

The spelling of 140445233113 in words is "one hundred forty billion, four hundred forty-five million, two hundred thirty-three thousand, one hundred thirteen".