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140454202153 = 499281471347
BaseRepresentation
bin1000001011001110111…
…0010000101100101001
3111102112111100201222011
42002303232100230221
54300122233432103
6144305044555521
713101405006556
oct2026356205451
9442474321864
10140454202153
115462580aa21
12232799b2ba1
1310324a00575
146b25aa1a2d
1539c0a3ed6d
hex20b3b90b29

140454202153 has 4 divisors (see below), whose sum is σ = 140735674000. Its totient is φ = 140172730308.

The previous prime is 140454202139. The next prime is 140454202171. The reversal of 140454202153 is 351202454041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140454202153 - 213 = 140454193961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140454202753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140735175 + ... + 140736172.

It is an arithmetic number, because the mean of its divisors is an integer number (35183918500).

Almost surely, 2140454202153 is an apocalyptic number.

It is an amenable number.

140454202153 is a deficient number, since it is larger than the sum of its proper divisors (281471847).

140454202153 is an equidigital number, since it uses as much as digits as its factorization.

140454202153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 281471846.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 140454202153 its reverse (351202454041), we get a palindrome (491656656194).

The spelling of 140454202153 in words is "one hundred forty billion, four hundred fifty-four million, two hundred two thousand, one hundred fifty-three".

Divisors: 1 499 281471347 140454202153