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14048563411011 = 334913134129249
BaseRepresentation
bin1100110001101110111110…
…1000011011100001000011
31211202000210112112211202210
43030123233220123201003
53320132424213123021
645513453153313203
72646655332500163
oct314335750334103
954660715484683
1014048563411011
114526a64889108
1216aa857565803
137aba0a1a40cc
14367d500845a3
1519567e5c1e76
hexcc6efa1b843

14048563411011 has 8 divisors (see below), whose sum is σ = 18731954538000. Its totient is φ = 9365440612352.

The previous prime is 14048563410991. The next prime is 14048563411027. The reversal of 14048563411011 is 11011436584041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14048563411011 - 215 = 14048563378243 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14048563411031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 66959886 + ... + 67169363.

It is an arithmetic number, because the mean of its divisors is an integer number (2341494317250).

Almost surely, 214048563411011 is an apocalyptic number.

14048563411011 is a deficient number, since it is larger than the sum of its proper divisors (4683391126989).

14048563411011 is a wasteful number, since it uses less digits than its factorization.

14048563411011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 134164165.

The product of its (nonzero) digits is 46080, while the sum is 39.

Adding to 14048563411011 its reverse (11011436584041), we get a palindrome (25059999995052).

The spelling of 14048563411011 in words is "fourteen trillion, forty-eight billion, five hundred sixty-three million, four hundred eleven thousand, eleven".

Divisors: 1 3 34913 104739 134129249 402387747 4682854470337 14048563411011