Base | Representation |
---|---|
bin | 10100011100100000101… |
… | …010101000001011110001 |
3 | 11222022120000210120110220 |
4 | 110130200222220023301 |
5 | 141004421100220340 |
6 | 2553241004243253 |
7 | 203336160636525 |
oct | 24344052501361 |
9 | 4868500716426 |
10 | 1405002351345 |
11 | 4a194922095a |
12 | 1a8370540529 |
13 | a26500a9a98 |
14 | 4c006b1dd85 |
15 | 268323cced0 |
hex | 14720aa82f1 |
1405002351345 has 16 divisors (see below), whose sum is σ = 2320520013312. Its totient is φ = 725162503680.
The previous prime is 1405002351253. The next prime is 1405002351349. The reversal of 1405002351345 is 5431532005041.
It is not a de Polignac number, because 1405002351345 - 27 = 1405002351217 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1405002351349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1510754752 + ... + 1510755681.
It is an arithmetic number, because the mean of its divisors is an integer number (145032500832).
Almost surely, 21405002351345 is an apocalyptic number.
1405002351345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1405002351345 is a deficient number, since it is larger than the sum of its proper divisors (915517661967).
1405002351345 is a wasteful number, since it uses less digits than its factorization.
1405002351345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3021510472.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 1405002351345 its reverse (5431532005041), we get a palindrome (6836534356386).
The spelling of 1405002351345 in words is "one trillion, four hundred five billion, two million, three hundred fifty-one thousand, three hundred forty-five".
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