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14050113374353 = 710559190089881
BaseRepresentation
bin1100110001110100110000…
…0001000100100010010001
31211202011210120002010202111
43030131030001010202101
53320144113010434403
645514311042345321
72650041623120560
oct314351401044221
954664716063674
1014050113374353
11452768a794551
1216ab00a65b241
137abbc633ab94
14368059c71bd7
151957206da56d
hexcc74c044891

14050113374353 has 8 divisors (see below), whose sum is σ = 16058793231360. Its totient is φ = 12041813718240.

The previous prime is 14050113374347. The next prime is 14050113374369. The reversal of 14050113374353 is 35347331105041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14050113374353 - 29 = 14050113373841 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14050113374303) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 94971028 + ... + 95118853.

It is an arithmetic number, because the mean of its divisors is an integer number (2007349153920).

Almost surely, 214050113374353 is an apocalyptic number.

It is an amenable number.

14050113374353 is a deficient number, since it is larger than the sum of its proper divisors (2008679857007).

14050113374353 is a wasteful number, since it uses less digits than its factorization.

14050113374353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 190100447.

The product of its (nonzero) digits is 226800, while the sum is 40.

Adding to 14050113374353 its reverse (35347331105041), we get a palindrome (49397444479394).

The spelling of 14050113374353 in words is "fourteen trillion, fifty billion, one hundred thirteen million, three hundred seventy-four thousand, three hundred fifty-three".

Divisors: 1 7 10559 73913 190089881 1330629167 2007159053479 14050113374353