Base | Representation |
---|---|
bin | 1000001011011010011… |
… | …0001110001000010011 |
3 | 111102122212002202211102 |
4 | 2002312212032020103 |
5 | 4300222110114011 |
6 | 144313530335015 |
7 | 13102531626344 |
oct | 2026646161023 |
9 | 442585082742 |
10 | 140502426131 |
11 | 5464aa58351 |
12 | 23291b8a46b |
13 | 103319b6472 |
14 | 6b2c2560cb |
15 | 39c4db873b |
hex | 20b698e213 |
140502426131 has 4 divisors (see below), whose sum is σ = 141343758192. Its totient is φ = 139661094072.
The previous prime is 140502426073. The next prime is 140502426133. The reversal of 140502426131 is 131624205041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 140502426131 - 26 = 140502426067 is a prime.
It is a super-2 number, since 2×1405024261312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 140502426094 and 140502426103.
It is not an unprimeable number, because it can be changed into a prime (140502426133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 420665780 + ... + 420666113.
It is an arithmetic number, because the mean of its divisors is an integer number (35335939548).
Almost surely, 2140502426131 is an apocalyptic number.
140502426131 is a deficient number, since it is larger than the sum of its proper divisors (841332061).
140502426131 is an equidigital number, since it uses as much as digits as its factorization.
140502426131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 841332060.
The product of its (nonzero) digits is 5760, while the sum is 29.
The spelling of 140502426131 in words is "one hundred forty billion, five hundred two million, four hundred twenty-six thousand, one hundred thirty-one".
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