Base | Representation |
---|---|
bin | 1100110001110101010001… |
… | …0011111101010101110001 |
3 | 1211202012011020221122201121 |
4 | 3030131110103331111301 |
5 | 3320144404122341340 |
6 | 45514332533302241 |
7 | 2650045233050224 |
oct | 314352423752561 |
9 | 54665136848647 |
10 | 14050252543345 |
11 | 45277512a9247 |
12 | 16ab049194981 |
13 | 7abc19116bb5 |
14 | 36807053b5bb |
15 | 19572ca2a94a |
hex | cc7544fd571 |
14050252543345 has 16 divisors (see below), whose sum is σ = 17091431298000. Its totient is φ = 11086734117888.
The previous prime is 14050252543337. The next prime is 14050252543391. The reversal of 14050252543345 is 54334525205041.
It can be written as a sum of positive squares in 8 ways, for example, as 6054084864 + 14044198458481 = 77808^2 + 3747559^2 .
It is a cyclic number.
It is not a de Polignac number, because 14050252543345 - 23 = 14050252543337 is a prime.
It is a super-2 number, since 2×140502525433452 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38416530 + ... + 38780539.
It is an arithmetic number, because the mean of its divisors is an integer number (1068214456125).
Almost surely, 214050252543345 is an apocalyptic number.
It is an amenable number.
14050252543345 is a deficient number, since it is larger than the sum of its proper divisors (3041178754655).
14050252543345 is an equidigital number, since it uses as much as digits as its factorization.
14050252543345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 77197572.
The product of its (nonzero) digits is 1440000, while the sum is 43.
Adding to 14050252543345 its reverse (54334525205041), we get a palindrome (68384777748386).
The spelling of 14050252543345 in words is "fourteen trillion, fifty billion, two hundred fifty-two million, five hundred forty-three thousand, three hundred forty-five".
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