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14050305433 = 52612670653
BaseRepresentation
bin11010001010111011…
…01010010110011001
31100021012010110122201
431011131222112121
5212233334233213
610242110450201
71005115424413
oct150535522631
940235113581
1014050305433
115a6003847a
122881503961
13142bb732c8
1497404d9b3
1557376d6dd
hex34576a599

14050305433 has 4 divisors (see below), whose sum is σ = 14052981348. Its totient is φ = 14047629520.

The previous prime is 14050305431. The next prime is 14050305509. The reversal of 14050305433 is 33450305041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6771314944 + 7278990489 = 82288^2 + 85317^2 .

It is a cyclic number.

It is not a de Polignac number, because 14050305433 - 21 = 14050305431 is a prime.

It is a super-2 number, since 2×140503054332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14050305431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1330066 + ... + 1340587.

It is an arithmetic number, because the mean of its divisors is an integer number (3513245337).

Almost surely, 214050305433 is an apocalyptic number.

It is an amenable number.

14050305433 is a deficient number, since it is larger than the sum of its proper divisors (2675915).

14050305433 is an equidigital number, since it uses as much as digits as its factorization.

14050305433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2675914.

The product of its (nonzero) digits is 10800, while the sum is 28.

The spelling of 14050305433 in words is "fourteen billion, fifty million, three hundred five thousand, four hundred thirty-three".

Divisors: 1 5261 2670653 14050305433