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140503143347 = 767299580263
BaseRepresentation
bin1000001011011010100…
…0111101001110110011
3111102122220110012122222
42002312220331032303
54300222301041342
6144313553551255
713102541004350
oct2026650751663
9442586405588
10140503143347
11546503a8196
122329227552b
1310331ba7a58
146b2c3a1627
1539c4eaaed2
hex20b6a3d3b3

140503143347 has 8 divisors (see below), whose sum is σ = 162971663616. Its totient is φ = 118633783752.

The previous prime is 140503143329. The next prime is 140503143371. The reversal of 140503143347 is 743341305041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 140503143347 - 26 = 140503143283 is a prime.

It is a super-2 number, since 2×1405031433472 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140503143317) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 149789663 + ... + 149790600.

It is an arithmetic number, because the mean of its divisors is an integer number (20371457952).

Almost surely, 2140503143347 is an apocalyptic number.

140503143347 is a deficient number, since it is larger than the sum of its proper divisors (22468520269).

140503143347 is an equidigital number, since it uses as much as digits as its factorization.

140503143347 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 299580337.

The product of its (nonzero) digits is 60480, while the sum is 35.

Adding to 140503143347 its reverse (743341305041), we get a palindrome (883844448388).

The spelling of 140503143347 in words is "one hundred forty billion, five hundred three million, one hundred forty-three thousand, three hundred forty-seven".

Divisors: 1 7 67 469 299580263 2097061841 20071877621 140503143347