1405053113 has 4 divisors (see below), whose sum is σ = 1405242768. Its totient is φ = 1404863460.

The previous prime is 1405053107. The next prime is 1405053121. The reversal of 1405053113 is 3113505041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3113505041 = 389 ⋅8003869.

It is a cyclic number.

It is not a de Polignac number, because 1405053113 - 2¹⁸ = 1404790969 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1405053193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83243 + ... + 98688.

It is an arithmetic number, because the mean of its divisors is an integer number (351310692).

Almost surely, 2^1405053113 is an apocalyptic number.

It is an amenable number.

1405053113 is a deficient number, since it is larger than the sum of its proper divisors (189655).

1405053113 is an equidigital number, since it uses as much as digits as its factorization.

1405053113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 189654.

The product of its (nonzero) digits is 900, while the sum is 23.

The square root of 1405053113 is about 37484.0381095741. The cubic root of 1405053113 is about 1120.0332454524.

Adding to 1405053113 its reverse (3113505041), we get a palindrome (4518558154).

The spelling of 1405053113 in words is "one billion, four hundred five million, fifty-three thousand, one hundred thirteen".