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140506535035 = 528101307007
BaseRepresentation
bin1000001011011011010…
…1111001010001111011
3111102200010211112012001
42002312311321101323
54300224133110120
6144314154401431
713102611561556
oct2026665712173
9442603745161
10140506535035
1154652304439
1223293430277
13103327c4779
146b2ca0569d
1539c542ae0a
hex20b6d7947b

140506535035 has 4 divisors (see below), whose sum is σ = 168607842048. Its totient is φ = 112405228024.

The previous prime is 140506535017. The next prime is 140506535053. The reversal of 140506535035 is 530535605041.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (140506535017) and next prime (140506535053).

It is a cyclic number.

It is not a de Polignac number, because 140506535035 - 211 = 140506532987 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140506534985 and 140506535003.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14050653499 + ... + 14050653508.

It is an arithmetic number, because the mean of its divisors is an integer number (42151960512).

Almost surely, 2140506535035 is an apocalyptic number.

140506535035 is a deficient number, since it is larger than the sum of its proper divisors (28101307013).

140506535035 is an equidigital number, since it uses as much as digits as its factorization.

140506535035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28101307012.

The product of its (nonzero) digits is 135000, while the sum is 37.

The spelling of 140506535035 in words is "one hundred forty billion, five hundred six million, five hundred thirty-five thousand, thirty-five".

Divisors: 1 5 28101307007 140506535035