Base | Representation |
---|---|
bin | 1000001011011011010… |
… | …1111001010001111011 |
3 | 111102200010211112012001 |
4 | 2002312311321101323 |
5 | 4300224133110120 |
6 | 144314154401431 |
7 | 13102611561556 |
oct | 2026665712173 |
9 | 442603745161 |
10 | 140506535035 |
11 | 54652304439 |
12 | 23293430277 |
13 | 103327c4779 |
14 | 6b2ca0569d |
15 | 39c542ae0a |
hex | 20b6d7947b |
140506535035 has 4 divisors (see below), whose sum is σ = 168607842048. Its totient is φ = 112405228024.
The previous prime is 140506535017. The next prime is 140506535053. The reversal of 140506535035 is 530535605041.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (140506535017) and next prime (140506535053).
It is a cyclic number.
It is not a de Polignac number, because 140506535035 - 211 = 140506532987 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 140506534985 and 140506535003.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14050653499 + ... + 14050653508.
It is an arithmetic number, because the mean of its divisors is an integer number (42151960512).
Almost surely, 2140506535035 is an apocalyptic number.
140506535035 is a deficient number, since it is larger than the sum of its proper divisors (28101307013).
140506535035 is an equidigital number, since it uses as much as digits as its factorization.
140506535035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28101307012.
The product of its (nonzero) digits is 135000, while the sum is 37.
The spelling of 140506535035 in words is "one hundred forty billion, five hundred six million, five hundred thirty-five thousand, thirty-five".
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