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14052035 = 52810407
BaseRepresentation
bin110101100110…
…101011000011
3222102220202202
4311212223003
512044131120
61221103415
7230304014
oct65465303
928386682
1014052035
117a28558
124857b6b
132bb001a
141c1b00b
151378875
hexd66ac3

14052035 has 4 divisors (see below), whose sum is σ = 16862448. Its totient is φ = 11241624.

The previous prime is 14052019. The next prime is 14052043. The reversal of 14052035 is 53025041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53025041 = 163325307.

It is a cyclic number.

It is not a de Polignac number, because 14052035 - 24 = 14052019 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14051998 and 14052016.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1405199 + ... + 1405208.

It is an arithmetic number, because the mean of its divisors is an integer number (4215612).

Almost surely, 214052035 is an apocalyptic number.

14052035 is a deficient number, since it is larger than the sum of its proper divisors (2810413).

14052035 is an equidigital number, since it uses as much as digits as its factorization.

14052035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2810412.

The product of its (nonzero) digits is 600, while the sum is 20.

The square root of 14052035 is about 3748.6044069760. The cubic root of 14052035 is about 241.3124566474.

Adding to 14052035 its reverse (53025041), we get a palindrome (67077076).

The spelling of 14052035 in words is "fourteen million, fifty-two thousand, thirty-five".

Divisors: 1 5 2810407 14052035