1405214113 has 4 divisors (see below), whose sum is σ = 1405294848. Its totient is φ = 1405133380.

The previous prime is 1405214081. The next prime is 1405214149. The reversal of 1405214113 is 3114125041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 1405214113 - 2⁵ = 1405214081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1405211113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2281 + ... + 53062.

It is an arithmetic number, because the mean of its divisors is an integer number (351323712).

Almost surely, 2^1405214113 is an apocalyptic number.

It is an amenable number.

1405214113 is a deficient number, since it is larger than the sum of its proper divisors (80735).

1405214113 is an equidigital number, since it uses as much as digits as its factorization.

1405214113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80734.

The product of its (nonzero) digits is 480, while the sum is 22.

The square root of 1405214113 is about 37486.1856288420. The cubic root of 1405214113 is about 1120.0760240168.

Adding to 1405214113 its reverse (3114125041), we get a palindrome (4519339154).

The spelling of 1405214113 in words is "one billion, four hundred five million, two hundred fourteen thousand, one hundred thirteen".